The sum of 4.6 and one-third a number is equal to at most 39.1. What are all the possible values of the number? Artem wrote the inequality 13n+4.6≤39.1

, where n equals the number, to help solve this problem. Solve his inequality.(1 point)

n≤131.1
n less than or equal to 131.1

n≤11.5
n less than or equal to 11.5

n≤103.5
n less than or equal to 103.5

n≤112.7

1 answer

To solve the problem, we start with the inequality described: the sum of 4.6 and one-third of a number \( n \) is equal to at most 39.1. We can express this as:

\[ 4.6 + \frac{1}{3}n \leq 39.1 \]

Next, we need to isolate \( n \). Let's subtract 4.6 from both sides:

\[ \frac{1}{3}n \leq 39.1 - 4.6 \]

Calculating the right-hand side:

\[ 39.1 - 4.6 = 34.5 \]

Now our inequality is:

\[ \frac{1}{3}n \leq 34.5 \]

To eliminate the fraction, we multiply both sides by 3:

\[ n \leq 34.5 \times 3 \]

Calculating the multiplication:

\[ 34.5 \times 3 = 103.5 \]

Thus, we have:

\[ n \leq 103.5 \]

This means that the possible values of the number \( n \) are all values that are less than or equal to 103.5. Therefore, the correct option is:

n ≤ 103.5
n less than or equal to 103.5