The sum of 4.6 and one-third a number is equal to at most 39.1. What are all the possible values of the number? Artem wrote the inequality 13n+4.6≤39.1

Question

, where n equals the number, to help solve this problem. Solve his inequality.(1 point)

n≤131.1
n less than or equal to 131.1

n≤11.5
n less than or equal to 11.5

n≤103.5
n less than or equal to 103.5

n≤112.7

Answer 1

To solve the problem, we start with the inequality described: the sum of 4.6 and one-third of a number $n$ is equal to at most 39.1. We can express this as:

$$4.6+\frac{1}{3}n\le 39.1$$

Next, we need to isolate $n$. Let's subtract 4.6 from both sides:

$$\frac{1}{3}n\le 39.1-4.6$$

Calculating the right-hand side:

$$39.1-4.6=34.5$$

Now our inequality is:

$$\frac{1}{3}n\le 34.5$$

To eliminate the fraction, we multiply both sides by 3:

$$n\le 34.5\times 3$$

Calculating the multiplication:

$$34.5\times 3=103.5$$

Thus, we have:

$$n\le 103.5$$

This means that the possible values of the number $n$ are all values that are less than or equal to 103.5. Therefore, the correct option is:

n ≤ 103.5
n less than or equal to 103.5