Question
The reaction of zinc (II) hydroxide with phosphoric acid produces zinc (II) phosphate and water.
Balance the reaction by completing the chemical equation with the molar coefficients
Zn(OH)² + H³PO⁴ → Zn³(PO⁴)2 + H₂O
2
3
4
5
6
Balance the reaction by completing the chemical equation with the molar coefficients
Zn(OH)² + H³PO⁴ → Zn³(PO⁴)2 + H₂O
2
3
4
5
6
Answers
GPT-4o mini
To balance the reaction between zinc(II) hydroxide \((\text{Zn(OH)}_2)\) and phosphoric acid \((\text{H}_3\text{PO}_4)\) that produces zinc(II) phosphate \((\text{Zn}_3(\text{PO}_4)_2)\) and water \((\text{H}_2\text{O})\), we start by writing the unbalanced equation:
\[
\text{Zn(OH)}_2 + \text{H}_3\text{PO}_4 \rightarrow \text{Zn}_3(\text{PO}_4)_2 + \text{H}_2\text{O}
\]
Next, we need to identify the number of each type of atom on both sides to ensure balanced coefficients.
1. **Zinc (Zn)**: In \(\text{Zn}_3(\text{PO}_4)_2\) there are 3 Zn.
2. **Phosphate (PO₄)**: In \(\text{Zn}_3(\text{PO}_4)_2\) there are 2 \(\text{PO}_4\), so we need 2 moles of \(\text{H}_3\text{PO}_4\).
3. **Water (H₂O)**: Each \(\text{Zn(OH)}_2\) provides 2 OH⁻ ions.
After some trial and error, we find the coefficients to balance the reaction:
The balanced equation will be:
\[
3 \, \text{Zn(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow 1 \, \text{Zn}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O}
\]
Thus, the corresponding coefficients are:
- **3** for \(\text{Zn(OH)}_2\)
- **2** for \(\text{H}_3\text{PO}_4\)
- **1** for \(\text{Zn}_3(\text{PO}_4)_2\)
- **6** for \(\text{H}_2\text{O}\)
The complete balanced equation can be stated as:
\[
3 \, \text{Zn(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow 1 \, \text{Zn}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O}
\]
So the answers to your question about the coefficients in order are: **3, 2, 1, 6**.
\[
\text{Zn(OH)}_2 + \text{H}_3\text{PO}_4 \rightarrow \text{Zn}_3(\text{PO}_4)_2 + \text{H}_2\text{O}
\]
Next, we need to identify the number of each type of atom on both sides to ensure balanced coefficients.
1. **Zinc (Zn)**: In \(\text{Zn}_3(\text{PO}_4)_2\) there are 3 Zn.
2. **Phosphate (PO₄)**: In \(\text{Zn}_3(\text{PO}_4)_2\) there are 2 \(\text{PO}_4\), so we need 2 moles of \(\text{H}_3\text{PO}_4\).
3. **Water (H₂O)**: Each \(\text{Zn(OH)}_2\) provides 2 OH⁻ ions.
After some trial and error, we find the coefficients to balance the reaction:
The balanced equation will be:
\[
3 \, \text{Zn(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow 1 \, \text{Zn}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O}
\]
Thus, the corresponding coefficients are:
- **3** for \(\text{Zn(OH)}_2\)
- **2** for \(\text{H}_3\text{PO}_4\)
- **1** for \(\text{Zn}_3(\text{PO}_4)_2\)
- **6** for \(\text{H}_2\text{O}\)
The complete balanced equation can be stated as:
\[
3 \, \text{Zn(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow 1 \, \text{Zn}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O}
\]
So the answers to your question about the coefficients in order are: **3, 2, 1, 6**.