Findtheminimumvalueoftheparabolay = x2.

Simplify your answer and write it as a proper fraction, improper fraction, or integer.

1 answer

The equation of the parabola given is \( y = x^2 \).

This is a standard quadratic function, where the coefficient of \( x^2 \) is positive (specifically, 1). Since the parabola opens upwards, its minimum value occurs at the vertex.

The vertex of the parabola given by \( y = x^2 \) can be found at \( x = 0 \).

To find the minimum value of \( y \):

\[ y = (0)^2 = 0 \]

Therefore, the minimum value of the parabola \( y = x^2 \) is \( \boxed{0} \).

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