Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
In the summer of 2008 the population of cuckoos in an area was estimated as 560 pairs. If the numbers returning are declining a...Asked by Golkhadi nep
In the summer of 2008 the population of cuckoos in an area was estimated as 560 pairs. If the numbers returning are declining at 4% each year, calculate
(a) the number of pairs of cuckoos in the area in the summer of 2009;
(b) the number of pairs of cuckoos in the area in the summer of 2020
(a) the number of pairs of cuckoos in the area in the summer of 2009;
(b) the number of pairs of cuckoos in the area in the summer of 2020
Answers
Answered by
Ariel
so my guess is that you would start with what ya got
2008 560-4%
2009 559.96-4%
2010 559.92-4%
(continue til you get to 2020)
sooo;
a.) 559.92
b.) 559.52
2008 560-4%
2009 559.96-4%
2010 559.92-4%
(continue til you get to 2020)
sooo;
a.) 559.92
b.) 559.52
Answered by
MathMate
If the population declines at 4%, it means that the surviving population is 96% of the previous year.
In the summer of 2008, there were 560 pairs. So in the summer of 2009, there were 560*(96/100)
= 537.6 pairs (theoretically)
= 538 pairs
In the summer of 2009, the population declined again to 96% of the theoretical population of 2008, thus
537.6*(96/100)
=516.1 pairs (theoretically)
= 516 pairs (rounded)
In the summer of 2008, there were 560 pairs. So in the summer of 2009, there were 560*(96/100)
= 537.6 pairs (theoretically)
= 538 pairs
In the summer of 2009, the population declined again to 96% of the theoretical population of 2008, thus
537.6*(96/100)
=516.1 pairs (theoretically)
= 516 pairs (rounded)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.