The lateral surface of a regular (right) pyramid is
A = (1/2) perimeter * slant height
Given A=160, and perimeter = 40,
try to figure out the slant height.
a.) 4cm
b.) 8cm
c.) 10cm
A = (1/2) perimeter * slant height
Given A=160, and perimeter = 40,
try to figure out the slant height.
Lateral Surface Area = (1/2) * Perimeter of Base * Slant Height
Given that the lateral surface area is 160 cm² and the perimeter of the base is 40 cm, we can substitute these values into the formula:
160 = (1/2) * 40 * Slant Height
Simplifying the equation:
160 = 20 * Slant Height
Dividing both sides of the equation by 20:
8 = Slant Height
Therefore, the slant height of the regular pyramid is 8 cm.
So, the answer is b.) 8cm.
Lateral Surface Area = (1/2) * Perimeter of Base * Slant Height
In this case, we are given that the lateral surface area is 160 cm^2 and the perimeter of the base is 40 cm. We can substitute these values into the formula and solve for the slant height.
160 = (1/2) * 40 * Slant Height
To isolate the slant height, we can divide both sides of the equation by (1/2) * 40:
160 / [(1/2) * 40] = Slant Height
Simplifying the expression:
160 / 20 = Slant Height
Slant Height = 8 cm
Therefore, the correct answer is b.) 8cm.