To find out how far the firework will travel before it reaches the ground, we need to solve the equation:
\[ 0 = -x^2 + 15x \]
This can be rearranged to:
\[ x^2 - 15x = 0 \]
Factoring out \(x\):
\[ x(x - 15) = 0 \]
Setting each factor equal to zero gives us:
- \( x = 0 \) (the initial point where the firework is launched)
- \( x - 15 = 0 \) which leads to \( x = 15 \)
Therefore, the firework will reach the ground again when \(x = 15\) feet.
The answer is: 15 feet.