To find which equation matches the solution set of {5}, we need to solve each equation for \( x \) to see if \( x = 5 \) is the only solution.
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\( 3x / 5 + 4 = 7 \)
\[ 3x / 5 = 7 - 4 \] \[ 3x / 5 = 3 \] \[ 3x = 15 \] \[ x = 5 \]
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\( x^2 - 10 = 15 \)
\[ x^2 = 15 + 10 \] \[ x^2 = 25 \] \[ x = 5 \quad \text{or} \quad x = -5 \]
This gives us two solutions, so it does not match the solution set of {5}.
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\( 2x - 20 = 30 \)
\[ 2x = 30 + 20 \] \[ 2x = 50 \] \[ x = 25 \]
This does not match the solution set of {5}.
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\( x + x - 9 = 1 + x \)
Simplifying this: \[ 2x - 9 = 1 + x \] Subtract \( x \) from both sides: \[ 2x - x - 9 = 1 \] \[ x - 9 = 1 \] \[ x = 10 \]
This does not match the solution set of {5}.
Based on the calculations, only the equation \( \frac{3x}{5} + 4 = 7 \) has the solution that matches the set {5}.
Final Answer: \( \frac{3x}{5} + 4 = 7 \)