By the Parallel line theorem
angle (JMN) = angle(JKL) and
angle(JNM) = angle(JLK)
DEFn : If 2 angles of one triangle are equal to 2 angles of another triangle, the two triangles are similar
If it is given that in triangleJKL that has a lineMN passing through it thatlineMN is parallel to line segmentKL, then prove that triangleJKL is similar to triangleJMN.
4 answers
.J
. .
M . .N
<---------->
. .
. .
K . . . . . . .L
this is what the figure looks like, but it needs to be either sss, sas, or aa similarity
. .
M . .N
<---------->
. .
. .
K . . . . . . .L
this is what the figure looks like, but it needs to be either sss, sas, or aa similarity
... and doesn't " aa similarity " mean you need two angles equal?
Look at my reply.
Look at my reply.
yes, thank you