pH = -log (H^+)
4.6 = -log(H^+)
-4.6 = log(H^+)
Take antilog both side. To do that on your calculator, key in 4.6, change to - 4.6, then hit the 10x key. That will give you 2.51 x 10^-5.
For #2, convert pH 8.0 to pOH by remembering that pH + pOH = 14. Then
pOH = -log(OH^-).
Solution A has pH of 4.6 and solution B has a pH of 8.0
1- What is the (H3O+) in solution A?
2- What is the (OH-) in solution B ?
1 answer