Question
The specific heat for iron is 0.450 J/g time K. A piece of iton increases from 27.2 degrees C t0 31.4 degrees C when of energy is added to it. What is the mass of the iron?
A. 1.65 x 10^-4 g
B. 343 g
C. 0.0029 g
D. 286 g
A. 1.65 x 10^-4 g
B. 343 g
C. 0.0029 g
D. 286 g
Answers
GPT-4o mini
To find the mass of the iron, we can use the formula for heat transfer:
\[
q = m \cdot c \cdot \Delta T
\]
Where:
- \( q \) is the heat energy added (in joules).
- \( m \) is the mass (in grams).
- \( c \) is the specific heat capacity (in J/g·K).
- \( \Delta T \) is the change in temperature (in degrees Celsius or Kelvin).
Given:
- Specific heat capacity (\( c \)) of iron = 0.450 J/g·K
- Initial temperature \( T_{1} = 27.2 \) degrees C
- Final temperature \( T_{2} = 31.4 \) degrees C
First, we calculate \( \Delta T \):
\[
\Delta T = T_{2} - T_{1} = 31.4 \, \text{°C} - 27.2 \, \text{°C} = 4.2 \, \text{°C}
\]
Now we rearrange the formula to solve for mass (\( m \)):
\[
m = \frac{q}{c \cdot \Delta T}
\]
However, since the problem does not provide a specific value for \( q \) (the energy added), we cannot calculate the mass exactly.
If you could provide the amount of energy added (in joules), I can compute the mass of the iron for you.
\[
q = m \cdot c \cdot \Delta T
\]
Where:
- \( q \) is the heat energy added (in joules).
- \( m \) is the mass (in grams).
- \( c \) is the specific heat capacity (in J/g·K).
- \( \Delta T \) is the change in temperature (in degrees Celsius or Kelvin).
Given:
- Specific heat capacity (\( c \)) of iron = 0.450 J/g·K
- Initial temperature \( T_{1} = 27.2 \) degrees C
- Final temperature \( T_{2} = 31.4 \) degrees C
First, we calculate \( \Delta T \):
\[
\Delta T = T_{2} - T_{1} = 31.4 \, \text{°C} - 27.2 \, \text{°C} = 4.2 \, \text{°C}
\]
Now we rearrange the formula to solve for mass (\( m \)):
\[
m = \frac{q}{c \cdot \Delta T}
\]
However, since the problem does not provide a specific value for \( q \) (the energy added), we cannot calculate the mass exactly.
If you could provide the amount of energy added (in joules), I can compute the mass of the iron for you.