Given a point on a line segment (−4, 5)

, what is the new point when the point is rotated counterclockwise about the origin 270 degrees?(1 point)

1 answer

To rotate a point \((x, y)\) counterclockwise about the origin by an angle \(\theta\), you can use the rotation formulas:

\[ x' = x \cos(\theta) - y \sin(\theta) \] \[ y' = x \sin(\theta) + y \cos(\theta) \]

In this case, the angle \(\theta\) is 270 degrees. First, we need to convert 270 degrees to radians:

\[ 270^\circ = \frac{3\pi}{2} \text{ radians} \]

Now, we find the cosine and sine of \(270^\circ\):

\[ \cos(270^\circ) = 0 \] \[ \sin(270^\circ) = -1 \]

Now, substitute the point \((-4, 5)\) into the rotation formulas:

\[ x' = -4 \cdot 0 - 5 \cdot (-1) = 0 + 5 = 5 \] \[ y' = -4 \cdot (-1) + 5 \cdot 0 = 4 + 0 = 4 \]

Thus, the new point after a 270 degree counterclockwise rotation is:

\[ (5, 4) \]

So, the final answer is \((5, 4)\).