To calculate \( \frac{2}{4} + \frac{3}{4} + \frac{3}{4} + \frac{3}{4} + 1 \) (liters), we can first convert all the fractions to have a common denominator and then add them together.
-
Start with the fractions: \[ \frac{2}{4} + \frac{3}{4} + \frac{3}{4} + \frac{3}{4} \]
-
Add the fractions: \[ \frac{2 + 3 + 3 + 3}{4} = \frac{11}{4} \]
-
Now, convert 1 to a fraction with a denominator of 4: \[ 1 = \frac{4}{4} \]
-
Now add \( \frac{11}{4} \) and \( \frac{4}{4} \): \[ \frac{11}{4} + \frac{4}{4} = \frac{11 + 4}{4} = \frac{15}{4} \]
-
Convert \( \frac{15}{4} \) to a mixed number: \[ \frac{15}{4} = 3 \frac{3}{4} \]
So the final answer is: \[ 3 \frac{3}{4} \text{ liters} \]
1 answer