Question

2/4+3/4+3/4+3/4+1 (liters)

Answer 1

To calculate \( \frac{2}{4} + \frac{3}{4} + \frac{3}{4} + \frac{3}{4} + 1 \) (liters), we can first convert all the fractions to have a common denominator and then add them together.

1. Start with the fractions:
\[
\frac{2}{4} + \frac{3}{4} + \frac{3}{4} + \frac{3}{4}
\]

2. Add the fractions:
\[
\frac{2 + 3 + 3 + 3}{4} = \frac{11}{4}
\]

3. Now, convert 1 to a fraction with a denominator of 4:
\[
1 = \frac{4}{4}
\]

4. Now add \( \frac{11}{4} \) and \( \frac{4}{4} \):
\[
\frac{11}{4} + \frac{4}{4} = \frac{11 + 4}{4} = \frac{15}{4}
\]

5. Convert \( \frac{15}{4} \) to a mixed number:
\[
\frac{15}{4} = 3 \frac{3}{4}
\]

So the final answer is:
\[
3 \frac{3}{4} \text{ liters}
\]