Which is the best description of Earth’s orbit?(1 point)

Question

Which is the best description of Earth’s orbit?(1 point)
Responses

parabolic
parabolic

circular
circular

highly elliptical
highly elliptical

almost circular
almost circular
Question 2
Which orbital shape did most scientists in the early 1600s think the planets of our solar system have?(1 point)
Responses

circular
circular

hyperbolic
hyperbolic

elliptical
elliptical

parabolic
parabolic
Question 3
Which planet’s orbit was Kepler first studying when he began to develop his laws of orbital motion?(1 point)
Responses

Mars
Mars

Earth
Earth

Jupiter
Jupiter

Saturn
Saturn
Question 4
Which of these describes Kepler’s third law of orbital motion?(1 point)
Responses

T³ ∝a²
T³ ∝a²

T²∝a
T²∝a

T∝a²
T∝a²

T² ∝ a³
  T² ∝ a³
Question 5
Which statement describes Kepler’s third law of orbital motion?(1 point)
Responses

The orbital period is proportional to the square of the semi-major axis. 
The orbital period is proportional to the square of the semi-major axis.

The cube of orbital period is proportional to the square of the semi-major axis. 
The cube of orbital period is proportional to the square of the semi-major axis.

The square of orbital period is proportional to the semi-major axis. 
The square of orbital period is proportional to the semi-major axis.

The square of orbital period is proportional to the cube of the semi-major axis.

GPT-4o mini · Answer

Here are the answers to each question: **Question 1: Which is the best description of Earth’s orbit?** **Answer:** almost circular --- **Question 2: Which orbital shape did most scientists in the early 1600s think the planets of our solar system have?** **Answer:** circular --- **Question 3: Which planet’s orbit was Kepler first studying when he began to develop his laws of orbital motion?** **Answer:** Mars --- **Question 4: Which of these describes Kepler’s third law of orbital motion?** **Answer:** T² ∝ a³ --- **Question 5: Which statement describes Kepler’s third law of orbital motion?** **Answer:** The square of orbital period is proportional to the cube of the semi-major axis. --- Let me know if you need more assistance!