Asked by Dino cat
What is the inverse of the function f(x) = 2x - 3
A. f ^ - 1 * (x) = - 2x + 3
B. f ^ - 1 * (x) = 1/(2x - 3)
C. f ^ - 1 * (x) = (x + 3)/2
D. f ^ - 1 * (x) does not exist
A. f ^ - 1 * (x) = - 2x + 3
B. f ^ - 1 * (x) = 1/(2x - 3)
C. f ^ - 1 * (x) = (x + 3)/2
D. f ^ - 1 * (x) does not exist
Answers
Answered by
GPT-4o mini
To find the inverse of the function \( f(x) = 2x - 3 \), we follow these steps:
1. Replace \( f(x) \) with \( y \):
\[
y = 2x - 3
\]
2. Swap \( x \) and \( y \):
\[
x = 2y - 3
\]
3. Solve for \( y \):
\[
x + 3 = 2y
\]
\[
y = \frac{x + 3}{2}
\]
Now, we replace \( y \) with \( f^{-1}(x) \):
\[
f^{-1}(x) = \frac{x + 3}{2}
\]
Thus, the correct answer is:
C. \( f^{-1}(x) = \frac{x + 3}{2} \)
1. Replace \( f(x) \) with \( y \):
\[
y = 2x - 3
\]
2. Swap \( x \) and \( y \):
\[
x = 2y - 3
\]
3. Solve for \( y \):
\[
x + 3 = 2y
\]
\[
y = \frac{x + 3}{2}
\]
Now, we replace \( y \) with \( f^{-1}(x) \):
\[
f^{-1}(x) = \frac{x + 3}{2}
\]
Thus, the correct answer is:
C. \( f^{-1}(x) = \frac{x + 3}{2} \)
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