To find the value of \(\tan x\) in the context of a right triangle, we need to understand what the dimensions you provided (length = 8 units, width = 10 feet, height = 6 units) signify.
It seems you might be referring to the dimensions of a box or a rectangular prism. If you're using these dimensions to set up a triangle, we could interpret them in a way involving angles.
For example, if you consider a right triangle where:
- The height (6) represents the opposite side of the triangle,
- The length (8) and/or width (10) could represent the adjacent side.
Assuming "height" refers to the opposite side of angle \(x\) and one of the other dimensions represents the adjacent side. We need to define which side we are using as adjacent.
Let's consider:
- If you take the height (6) as the opposite side,
- And one of the bases (say length = 8) as the adjacent side, then:
\[ \tan x = \frac{\text{opposite}}{\text{adjacent}} = \frac{6}{8} = \frac{3}{4}. \]
So, the value of \(\tan x\) would be \(\frac{3}{4}\).
If the adjacent side was defined differently, substitute the appropriate values into the tangent formula. The principles will remain the same.