Question

Find the perimeter and area of the rectangle that is 55 fttimes52 ft.

Answer 1

To find the perimeter and area of a rectangle, you can use the following formulas:

1. **Area (A)** of a rectangle is given by:
\[
A = \text{length} \times \text{width}
\]

2. **Perimeter (P)** of a rectangle is given by:
\[
P = 2 \times (\text{length} + \text{width})
\]

Given a rectangle with dimensions 55 ft (length) and 52 ft (width):

1. **Calculate the area**:
\[
A = 55 \, \text{ft} \times 52 \, \text{ft} = 2860 \, \text{ft}^2
\]

2. **Calculate the perimeter**:
\[
P = 2 \times (55 \, \text{ft} + 52 \, \text{ft}) = 2 \times 107 \, \text{ft} = 214 \, \text{ft}
\]

Thus, the area of the rectangle is **2860 ft²** and the perimeter is **214 ft**.