solution to the equation 4^2+3+1=0

1 answer

Let's simplify the equation:

\[ 4^2 + 3 + 1 = 0. \]

Calculating \( 4^2 \):

\[ 4^2 = 16. \]

Now substituting this back into the equation:

\[ 16 + 3 + 1 = 0. \]

Now simplify the left-hand side:

\[ 16 + 3 = 19, \] \[ 19 + 1 = 20. \]

So, we have:

\[ 20 = 0. \]

This is a contradiction, which means that the equation \( 4^2 + 3 + 1 = 0 \) has no solutions.