To combine the expression \( \log_3 z + \log_3 2 + \log_3 4 \) into a single logarithm, we can use the property of logarithms that states \( \log_a b + \log_a c = \log_a (bc) \).
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Start with the original expression: \[ \log_3 z + \log_3 2 + \log_3 4 \]
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Combine the first two terms: \[ \log_3(z \cdot 2) = \log_3(2z) \]
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Now include the third term: \[ \log_3(2z) + \log_3 4 = \log_3(2z \cdot 4) = \log_3(8z) \]
Thus, the expression \( \log_3 z + \log_3 2 + \log_3 4 \) can be rewritten as: \[ \log_3 (8z) \]
Therefore, the correct response is: \[ \text{logarithm subscript 3 baseline left parenthesis 8 z right parenthesis} \]
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