Asked by johnny

howdy, just cant seem to get this question, can anyone express this question in words i can get?! thanks

A sound wave of wavelength 0.8 m divides into two equal parts that recombine to interfere constructively, with the original difference between their path lengths being |r2|-|r1| = 0.8 m. Rank the following situations according to the intensity of sound at the receiver from the highest to the lowest. Assume the tube walls absorb no sound energy.

*The figure is two U shaped pipes with them shaped like opposite horseshoes, and at the junctions where they meet are holes for the sounding device and the other for the listener

Answers

Answered by Soli
a. If the tube is moved by 0.1 m, r2 increases by 0.2m, so r2-r1 is now 0.1m. Therefore lambda is (2pi/0.8)(0.1)=2.5pi
--> Intensity=I cos squared(2.5pi/2)

You pretty much d that for each one and you get d>a=c>b
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