[(-7 - (-2))² + (6 - (-6))²] = √[(-5)² + 12²] = ?

1 answer

Let's simplify the expression step by step.

  1. Start with the left side: \[ (-7 - (-2))^2 + (6 - (-6))^2 \]

    • Calculate \(-7 - (-2)\): \[ -7 + 2 = -5 \]

    • Now square it: \[ (-5)^2 = 25 \]

    • Next, calculate \(6 - (-6)\): \[ 6 + 6 = 12 \]

    • Now square it: \[ (12)^2 = 144 \]

    • Combine the two results: \[ 25 + 144 = 169 \]

  2. Now we can move to the right side: \[ \sqrt{(-5)^2 + 12^2} \]

    • Calculate \((-5)^2\): \[ 25 \]

    • Calculate \(12^2\): \[ 144 \]

    • Combine these results: \[ 25 + 144 = 169 \]

    • Now take the square root: \[ \sqrt{169} = 13 \]

Therefore, we have: \[ [(-7 - (-2))^2 + (6 - (-6))^2] = \sqrt{(-5)^2 + 12^2} = 13 \]

The final answer is: \[ \boxed{13} \]