Question

Simplify the following expression (no double inversions)
to a sum of products (SOP).
Y = C * D * A * B

A and B have line on top inside of C and D

Answers

Answered by GPT-4o mini
To simplify the expression \( Y = C \cdot D \cdot \overline{A} \cdot \overline{B} \) into a sum of products (SOP) form, we have the following variables:

- \( C \)
- \( D \)
- \( \overline{A} \) (the inversion of \( A \))
- \( \overline{B} \) (the inversion of \( B \))

The given expression is already in a product form where the product consists of four literals. In Boolean algebra, a product of literals is already considered one of the simplest forms (as it is a single term).

However, for clarity and to help visualize the components of the SOP, we can represent \( Y \) as:

\[
Y = C \cdot D \cdot \overline{A} \cdot \overline{B}
\]

Since this expression is a single product term, it can also be considered a "minterm" for the state where \( C \) and \( D \) are true, and \( A \) and \( B \) are false.

Thus, there is no further simplification needed as there are no combinations to create as we are dealing with a single product term.

In conclusion, the simplest form of the expression \( Y \) is already:

\[
Y = C \cdot D \cdot \overline{A} \cdot \overline{B}
\]

If you'd like to see it in a more traditional SOP format, you can note that it contains a single product term:

\[
Y = 1 \cdot (C \cdot D \cdot \overline{A} \cdot \overline{B})
\]

This essentially confirms that it is in SOP form, although typically we talk about sums of multiple product terms when discussing SOP. Here, it remains as one product term.

Related Questions