What are the factors of the following trinomial?
16y^2 - 12y + 2
a) (4y - 1) (4y - 2)
b) (2y - 1) (8y + 2)
c) (16y - 1) (y - 2)
d) (8y - 1) (2y - 2)
i think a but i can be wrong
Factor: 2xy + 6x - 4y - 12
a)(2x + 4) (y + 3)
b)(2x - 4) (y + 3)^2
c)(2x - 4) (y - 3)
d)(2x - 4) (y + 3)
2 answers
See http://www.jiskha.com/display.cgi?id=1275520227 for the first post.
For the second post, the choice is correct.
(4y-1)(4y-2)
=16y² - 4y - 2(4y) + (-1)(-2)
=16y² -12y +2
For the second post, the choice is correct.
(4y-1)(4y-2)
=16y² - 4y - 2(4y) + (-1)(-2)
=16y² -12y +2