Asked by bots lover
How many solution(s) does the system of equations have?
−5x+y=−18
10x−2y=36
(1 point)
Responses
two
two
one
one
none
none
infinite
−5x+y=−18
10x−2y=36
(1 point)
Responses
two
two
one
one
none
none
infinite
Answers
Answered by
GPT-4o mini
To determine how many solutions the system of equations has, we can analyze the two equations given:
1. \( -5x + y = -18 \)
2. \( 10x - 2y = 36 \)
We can rearrange both equations into slope-intercept form (y = mx + b) or analyze them directly.
First, let's simplify the second equation:
From \( 10x - 2y = 36 \), we can isolate \( y \):
\[
-2y = -10x + 36
\]
\[
y = 5x - 18
\]
Now we can write the first equation in slope-intercept form:
From \( -5x + y = -18 \), rearranging gives:
\[
y = 5x - 18
\]
Now we have:
1. \( y = 5x - 18 \) (first equation)
2. \( y = 5x - 18 \) (second equation)
Both equations are equivalent (they produce the same line), meaning they represent the same line on a graph.
Therefore, the system has **infinite solutions** because every point on the line is a solution to the system of equations.
The answer is **infinite**.
1. \( -5x + y = -18 \)
2. \( 10x - 2y = 36 \)
We can rearrange both equations into slope-intercept form (y = mx + b) or analyze them directly.
First, let's simplify the second equation:
From \( 10x - 2y = 36 \), we can isolate \( y \):
\[
-2y = -10x + 36
\]
\[
y = 5x - 18
\]
Now we can write the first equation in slope-intercept form:
From \( -5x + y = -18 \), rearranging gives:
\[
y = 5x - 18
\]
Now we have:
1. \( y = 5x - 18 \) (first equation)
2. \( y = 5x - 18 \) (second equation)
Both equations are equivalent (they produce the same line), meaning they represent the same line on a graph.
Therefore, the system has **infinite solutions** because every point on the line is a solution to the system of equations.
The answer is **infinite**.
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