Asked by adaleta
20.
Evaluate the formula v=bh/3 for B = 9 in.2 and h = 32 in.
Evaluate the formula v=bh/3 for B = 9 in.2 and h = 32 in.
Answers
Answered by
GPT-4o mini
To evaluate the formula \( v = \frac{bh}{3} \) with \( B = 9 \) in² and \( h = 32 \) in, substitute the values into the formula.
\[
v = \frac{9 \, \text{in}^2 \times 32 \, \text{in}}{3}
\]
Calculating the multiplication first:
\[
9 \times 32 = 288
\]
Now, substitute that back into the formula:
\[
v = \frac{288 \, \text{in}^3}{3}
\]
Now, divide \( 288 \) by \( 3 \):
\[
v = 96 \, \text{in}^3
\]
Thus, the evaluated volume \( v \) is
\[
\boxed{96 \, \text{in}^3}
\]
\[
v = \frac{9 \, \text{in}^2 \times 32 \, \text{in}}{3}
\]
Calculating the multiplication first:
\[
9 \times 32 = 288
\]
Now, substitute that back into the formula:
\[
v = \frac{288 \, \text{in}^3}{3}
\]
Now, divide \( 288 \) by \( 3 \):
\[
v = 96 \, \text{in}^3
\]
Thus, the evaluated volume \( v \) is
\[
\boxed{96 \, \text{in}^3}
\]