To directly lift a crate 0.6 meters, Joaquin would need to apply 312 newtons of force. Instead, he uses a lever with a mechanical advantage of 3 to lift the crate. How much force does he save by using the lever?(1 point)

Question

Responses

309 N
309 N

936 N
936 N

104 N
104 N

208 N

Answer 1

To determine how much force Joaquin saves by using a lever with a mechanical advantage of 3, we first need to calculate the force he would need to apply using the lever.

The mechanical advantage (MA) of a lever is defined as the ratio of the output force (the force needed to lift the crate) to the input force (the force exerted by Joaquin):

\[ \text{MA} = \frac{\text{Output Force}}{\text{Input Force}} \]

Given that the mechanical advantage is 3, we can rearrange the formula to find the input force (the force Joaquin needs to exert):

\[ \text{Input Force} = \frac{\text{Output Force}}{\text{MA}} = \frac{312 \text{ N}}{3} = 104 \text{ N} \]

Now, to find out how much force he saves, we subtract the input force from the output force:

\[ \text{Force Saved} = \text{Output Force} - \text{Input Force} = 312 \text{ N} - 104 \text{ N} = 208 \text{ N} \]

Therefore, the amount of force Joaquin saves by using the lever is 208 N.