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To directly lift a crate 0.6 meters, Joaquin would need to apply 312 newtons of force. Instead, he uses a lever with a mechanic...Asked by burnout
                To directly lift a crate 0.6 meters, Joaquin would need to apply 312 newtons of force. Instead, he uses a lever with a mechanical advantage of 3 to lift the crate. How much force does he save by using the lever?(1 point)
Responses
309 N
309 N
936 N
936 N
104 N
104 N
208 N
            
        Responses
309 N
309 N
936 N
936 N
104 N
104 N
208 N
Answers
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                    Answered by
            GPT-4o mini
            
    To determine how much force Joaquin saves by using a lever with a mechanical advantage of 3, we first need to calculate the force he would need to apply using the lever.
The mechanical advantage (MA) of a lever is defined as the ratio of the output force (the force needed to lift the crate) to the input force (the force exerted by Joaquin):
\[
\text{MA} = \frac{\text{Output Force}}{\text{Input Force}}
\]
Given that the mechanical advantage is 3, we can rearrange the formula to find the input force (the force Joaquin needs to exert):
\[
\text{Input Force} = \frac{\text{Output Force}}{\text{MA}} = \frac{312 \text{ N}}{3} = 104 \text{ N}
\]
Now, to find out how much force he saves, we subtract the input force from the output force:
\[
\text{Force Saved} = \text{Output Force} - \text{Input Force} = 312 \text{ N} - 104 \text{ N} = 208 \text{ N}
\]
Therefore, the amount of force Joaquin saves by using the lever is **208 N**.
    
The mechanical advantage (MA) of a lever is defined as the ratio of the output force (the force needed to lift the crate) to the input force (the force exerted by Joaquin):
\[
\text{MA} = \frac{\text{Output Force}}{\text{Input Force}}
\]
Given that the mechanical advantage is 3, we can rearrange the formula to find the input force (the force Joaquin needs to exert):
\[
\text{Input Force} = \frac{\text{Output Force}}{\text{MA}} = \frac{312 \text{ N}}{3} = 104 \text{ N}
\]
Now, to find out how much force he saves, we subtract the input force from the output force:
\[
\text{Force Saved} = \text{Output Force} - \text{Input Force} = 312 \text{ N} - 104 \text{ N} = 208 \text{ N}
\]
Therefore, the amount of force Joaquin saves by using the lever is **208 N**.
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