To find the force that Sarah expends using the inclined plane, we can use the work formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
In this scenario, if we assume Sarah is applying the force parallel to the incline (which simplifies the situation), then \(\theta\) would be 0 degrees. Therefore, \(\cos(0) = 1\), and the formula simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Given the work done (84 Joules) and the distance (3 meters), we can rearrange the formula to solve for force:
\[ \text{Force} = \frac{\text{Work}}{\text{Distance}} \]
Substituting in the values:
\[ \text{Force} = \frac{84 \text{ Joules}}{3 \text{ meters}} = 28 \text{ N} \]
Thus, Sarah expends 28 N of force.
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