Anne exerts a force of 34.1 N to pitch a softball. She moves the ball 1.8 meters before releasing it. What amount of work did Anne do on the ball?(1 point)

Question

Responses

35.9 J
35.9 J

32.3 J
32.3 J

18.9 J
18.9 J

61.38 J

Answer 1

To determine the work done by Anne on the softball, we can use the work formula:

\[ \text{Work} (W) = \text{Force} (F) \times \text{Distance} (d) \times \cos(\theta) \]

Where:

• \( W \) is the work done (in joules),
• \( F \) is the force applied (in newtons),
• \( d \) is the distance moved by the object (in meters),
• \( \theta \) is the angle between the force and the direction of motion.

Since Anne exerts the force in the direction of the ball's motion, \( \theta = 0 \) degrees and \( \cos(0) = 1 \).

Given:

• \( F = 34.1 , \text{N} \)
• \( d = 1.8 , \text{m} \)

Now we can calculate the work done:

\[ W = 34.1 , \text{N} \times 1.8 , \text{m} \times 1 \]

\[ W = 34.1 \times 1.8 = 61.38 , \text{J} \]

Therefore, the amount of work that Anne did on the ball is 61.38 J.