For which type of function does the average rate of change produce the same value for any interval of the domain on the function? Why does this occur for this type of function?

*Hint* you have 3 choices: Linear, Quadratic and Exponential

1 answer

The type of function for which the average rate of change produces the same value for any interval of the domain is a Linear function.

Why does this occur for linear functions?

A linear function can be expressed in the form \( f(x) = mx + b \), where \( m \) is the slope (rate of change) and \( b \) is the y-intercept. The average rate of change of a linear function over any interval \([x_1, x_2]\) can be calculated using the formula:

\[ \text{Average Rate of Change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \]

Substituting the linear function into this formula gives:

\[ \text{Average Rate of Change} = \frac{(mx_2 + b) - (mx_1 + b)}{x_2 - x_1} = \frac{mx_2 - mx_1}{x_2 - x_1} = m \]

In this case, the average rate of change simplifies to just \( m \), the slope of the linear function, which is constant regardless of the choice of \( x_1 \) and \( x_2 \). Consequently, the average rate of change is the same for any interval on the linear function's domain.

In contrast:

  • Quadratic functions (e.g., \( f(x) = ax^2 + bx + c \)) have a variable rate of change that depends on the specific interval, as the slope increases or decreases depending on the values of \( x \).

  • Exponential functions (e.g., \( f(x) = a \cdot b^x \)) also have a varying rate of change that changes based on the base and the specific values of \( x \) over intervals.

Therefore, only linear functions produce a constant average rate of change across any interval in their domain.