To find the area of triangle \( ABC \) using the trigonometric area formula, we can use the following formula:
\[ \text{Area} = \frac{1}{2}ab \sin(C) \]
where:
- \( a \) and \( b \) are the lengths of two sides of the triangle,
- \( C \) is the angle between those two sides.
Given:
- \( a = 7 \) inches
- \( b = 12 \) inches
- \( C = 77^\circ \)
Now, let's substitute the values into the formula:
\[ \text{Area} = \frac{1}{2} \times 7 \times 12 \times \sin(77^\circ) \]
First, calculate \( \sin(77^\circ) \):
\[ \sin(77^\circ) \approx 0.97437 \]
Now substitute this value back into the area formula:
\[ \text{Area} \approx \frac{1}{2} \times 7 \times 12 \times 0.97437 \]
Calculating further:
\[ \text{Area} \approx \frac{1}{2} \times 84 \times 0.97437 \] \[ \text{Area} \approx 42 \times 0.97437 \] \[ \text{Area} \approx 40.99 \text{ square inches} \]
Rounding to the nearest inch, the area is approximately:
\[ \text{Area} \approx 41 \text{ square inches} \]
Thus, the area of triangle \( ABC \) is 41 inches².