Use the image to answer the question.

A number line is shown ranging from negative 10 to 10 with numbers listed in unit increments. A closed point is plotted on the number line between 2 and 3, just after the 2. A leftward arrow is marked on the number line that originates at the closed point and goes beyond negative 10.

Amari solved an inequality and graphed the solution on the number line. Which of the following inequalities did he solve?

(1 point)
Responses

2.8x+0.9≤6.5
2.8 x plus 0.9 is less than or equal to 6.5

4.9x+1.2≥11.49
4.9 x plus 1.2 greater than or equal to 11.49

3.7x−1.4≥6.37
3.7 x minus 1.4 greater than or equal to 6.37

3.2x−1.4≤5.32

1 answer

To determine which inequality Amari solved, we can analyze the positioning of the closed point on the number line. The point is located between 2 and 3, suggesting it represents a value that is greater than or equal to 2 but less than or equal to 3.

Let's convert the possible inequalities into their solutions to see which one aligns with the position of the closed point:

  1. For the first inequality: \(2.8x + 0.9 \leq 6.5\)

    Subtract 0.9 from both sides: \[ 2.8x \leq 5.6 \] Divide by 2.8: \[ x \leq 2 \] (This doesn't match the point which is greater than 2.)

  2. For the second inequality: \(4.9x + 1.2 \geq 11.49\)

    Subtract 1.2 from both sides: \[ 4.9x \geq 10.29 \] Divide by 4.9: \[ x \geq 2.1 \] (This also doesn't match because we need a closed interval at the point.)

  3. For the third inequality: \(3.7x - 1.4 \geq 6.37\)

    Add 1.4 to both sides: \[ 3.7x \geq 7.77 \] Divide by 3.7: \[ x \geq 2.1 \] (This gives a value greater than the closed point.)

  4. For the fourth inequality: \(3.2x - 1.4 \leq 5.32\)

    Add 1.4 to both sides: \[ 3.2x \leq 6.72 \] Divide by 3.2: \[ x \leq 2.1 \] This implies \( x \) could take values less than or equal to approximately 2.1, which includes values from 2 up to 2.1.

Since the closed point is greater than 2 and extends leftward (since it's closed, it includes 2.1), Amari likely solved the fourth inequality, \(3.2x - 1.4 \leq 5.32\). Thus, that matches well with the closed point being plotted just over 2.

Therefore, the correct response is: 3.2x−1.4≤5.32.