Asked by Halle
A student dissolves 0.550 mol of a nonvolatile, nonelectrolyte solute in one kilogram of benzene (C6H6). What is the boiling point elevation of the resulting solution?
in degrees celsius
in degrees celsius
Answers
Answered by
DrBob222
m = moles solute/kg solvent. Solve for m and substitute in the following:
delta T = Kb*m
Then add delta T to the normal boiling point.
delta T = Kb*m
Then add delta T to the normal boiling point.
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