Use the image to answer the question.

Question

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.

Translate figure PQRS
6 units down and 2 units to the right. What are the coordinates of P′
?

(1 point)
Responses

(6, 0)
left parenthesis 6 comma 0 right parenthesis

(10, 4)
left parenthesis 10 comma 4 right parenthesis

(2, 12)
left parenthesis 2 comma 12 right parenthesis

(2, 0)
left parenthesis 2 comma 0 right parenthesis
Skip to navigation

Answer 1

To find the new coordinates of point P after translating it 6 units down and 2 units to the right, we can start with the original coordinates of P, which are (4, 6).

1. Translate 2 units to the right:

   • For the x-coordinate: \(4 + 2 = 6\)

2. Translate 6 units down:

   • For the y-coordinate: \(6 - 6 = 0\)

Thus, the new coordinates of point P' after the translation are \( (6, 0) \).

The correct response is \( (6, 0) \).