Let's define the variables:
- Let \( x \) be the number of days from now.
- Millersburg Cars has already sold 10 cars and sells 2 cars per day, so the total number of cars sold by Millersburg Cars after \( x \) days will be \( 10 + 2x \).
- Norman's Autos has already sold 7 cars and sells 5 cars per day, so the total number of cars sold by Norman's Autos after \( x \) days will be \( 7 + 5x \).
We can set up the following equation to find when both dealerships have sold the same number of cars:
\[ 10 + 2x = 7 + 5x \]
Now, let's solve for \( x \).
- Start by subtracting \( 2x \) from both sides:
\[ 10 = 7 + 5x - 2x \] \[ 10 = 7 + 3x \]
- Next, subtract 7 from both sides:
\[ 10 - 7 = 3x \] \[ 3 = 3x \]
- Divide both sides by 3:
\[ x = 1 \]
Now we know it will take 1 day for the two dealerships to be tied.
Next, we can find out how many cars each lot will have sold after 1 day:
- For Millersburg Cars:
\[ 10 + 2(1) = 10 + 2 = 12 \]
- For Norman's Autos:
\[ 7 + 5(1) = 7 + 5 = 12 \]
After 1 day, both dealerships will have sold 12 cars.
So, to fill in the blanks:
In 1 day, the dealerships will each have sold 12 cars.