Let's denote the number of copies Fred wants to make as \( x \). We can set up a system of equations based on the costs of each option.
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Cost for the printer: \[ C_1 = 45 + 6x \] where \( C_1 \) is the total cost when using the printer.
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Cost for the office supply store: \[ C_2 = 28 + 7x \] where \( C_2 \) is the total cost when using the office supply store.
To find the number of copies that make the costs equivalent, we can set up the equation: \[ 45 + 6x = 28 + 7x \]
Now, let's solve for \( x \).
First, subtract \( 6x \) from both sides: \[ 45 = 28 + x \]
Next, subtract 28 from both sides: \[ 45 - 28 = x \] \[ 17 = x \]
Now, we know that \( x = 17 \). This means that the two options will cost the same when Fred makes 17 copies.
Next, we can calculate the cost for either option when \( x = 17 \). We'll use the printer's cost equation: \[ C_1 = 45 + 6(17) \] \[ C_1 = 45 + 102 \] \[ C_1 = 147 \]
Thus, the two options are equivalent when Fred makes 17 copies, and the cost would be $147.
Filling in the blanks, we have:
For 17 copies, the cost is $147.