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Solve using substitution. 8x − 3y = –8 10x − 7y = 16Asked by answer now
Solve using substitution.
x − 3y = 8
4x − 7y = 17
(
,
)
x − 3y = 8
4x − 7y = 17
(
,
)
Answers
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Answered by
GPT-4o mini
To solve the system of equations using substitution, we will first solve one of the equations for one variable and then substitute that expression into the other equation.
Given the equations:
1. \( x - 3y = 8 \) (Equation 1)
2. \( 4x - 7y = 17 \) (Equation 2)
### Step 1: Solve Equation 1 for \( x \)
From Equation 1:
\[
x = 3y + 8
\]
### Step 2: Substitute \( x \) in Equation 2
Now we will substitute \( x \) in Equation 2:
\[
4(3y + 8) - 7y = 17
\]
### Step 3: Simplify and solve for \( y \)
Distributing the 4:
\[
12y + 32 - 7y = 17
\]
Combine like terms:
\[
12y - 7y + 32 = 17
\]
\[
5y + 32 = 17
\]
Now, subtract 32 from both sides:
\[
5y = 17 - 32
\]
\[
5y = -15
\]
Divide by 5:
\[
y = -3
\]
### Step 4: Substitute \( y \) back into the expression for \( x \)
Now that we have \( y \), we substitute it back into the expression for \( x \):
\[
x = 3(-3) + 8
\]
Calculate:
\[
x = -9 + 8
\]
\[
x = -1
\]
### Solution
The solution to the system of equations is:
\[
(x, y) = (-1, -3)
\]
So the final answer is:
\[
(-1, -3)
\]
Given the equations:
1. \( x - 3y = 8 \) (Equation 1)
2. \( 4x - 7y = 17 \) (Equation 2)
### Step 1: Solve Equation 1 for \( x \)
From Equation 1:
\[
x = 3y + 8
\]
### Step 2: Substitute \( x \) in Equation 2
Now we will substitute \( x \) in Equation 2:
\[
4(3y + 8) - 7y = 17
\]
### Step 3: Simplify and solve for \( y \)
Distributing the 4:
\[
12y + 32 - 7y = 17
\]
Combine like terms:
\[
12y - 7y + 32 = 17
\]
\[
5y + 32 = 17
\]
Now, subtract 32 from both sides:
\[
5y = 17 - 32
\]
\[
5y = -15
\]
Divide by 5:
\[
y = -3
\]
### Step 4: Substitute \( y \) back into the expression for \( x \)
Now that we have \( y \), we substitute it back into the expression for \( x \):
\[
x = 3(-3) + 8
\]
Calculate:
\[
x = -9 + 8
\]
\[
x = -1
\]
### Solution
The solution to the system of equations is:
\[
(x, y) = (-1, -3)
\]
So the final answer is:
\[
(-1, -3)
\]
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