Question

Solve using substitution.

y = –5
4x − 8y = 16

Answer 1

To solve the system of equations using substitution, we start with the two equations given:

1. \( y = -5 \)
2. \( 4x - 8y = 16 \)

We can substitute the value of \( y \) from the first equation into the second equation.

Substituting \( y = -5 \) into the second equation:

\[
4x - 8(-5) = 16
\]

This simplifies to:

\[
4x + 40 = 16
\]

Next, isolate \( x \):

\[
4x = 16 - 40
\]

\[
4x = -24
\]

Now, divide by 4:

\[
x = -6
\]

Now we have the solutions for both \( x \) and \( y \):

\[
x = -6, \quad y = -5
\]

Thus, the solution to the system of equations is:

\[
\boxed{(-6, -5)}
\]