Solve using substitution.

y = –5
4x − 8y = 16

1 answer

To solve the system of equations using substitution, we start with the two equations given:

  1. \( y = -5 \)
  2. \( 4x - 8y = 16 \)

We can substitute the value of \( y \) from the first equation into the second equation.

Substituting \( y = -5 \) into the second equation:

\[ 4x - 8(-5) = 16 \]

This simplifies to:

\[ 4x + 40 = 16 \]

Next, isolate \( x \):

\[ 4x = 16 - 40 \]

\[ 4x = -24 \]

Now, divide by 4:

\[ x = -6 \]

Now we have the solutions for both \( x \) and \( y \):

\[ x = -6, \quad y = -5 \]

Thus, the solution to the system of equations is:

\[ \boxed{(-6, -5)} \]

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