The atomic mass and abundance of Si-28 is 27.977 amu and 92.2%. The atomic mass and abundance of Si-29 is 28.976 amu and 4.7%. The atomic mass and abundance of Si-30 is 29.974 amu and 3.1%. Which is the average atomic mass of silicon?

1 answer

To calculate the average atomic mass of silicon, we can use the formula for weighted averages based on the abundances and atomic masses of its isotopes.

The average atomic mass \( M \) can be calculated using:

\[ M = (m_1 \cdot a_1) + (m_2 \cdot a_2) + (m_3 \cdot a_3) \]

where \( m_1, m_2, m_3 \) are the atomic masses of the isotopes and \( a_1, a_2, a_3 \) are their respective abundances expressed as fractions.

Let's calculate each part:

  1. Silicon-28:

    • Atomic mass (\( m_1 \)): 27.977 amu
    • Abundance (\( a_1 \)): 92.2% = 0.922

    Contribution to average atomic mass: \[ m_1 \cdot a_1 = 27.977 \cdot 0.922 = 25.758 \]

  2. Silicon-29:

    • Atomic mass (\( m_2 \)): 28.976 amu
    • Abundance (\( a_2 \)): 4.7% = 0.047

    Contribution to average atomic mass: \[ m_2 \cdot a_2 = 28.976 \cdot 0.047 = 1.360 \]

  3. Silicon-30:

    • Atomic mass (\( m_3 \)): 29.974 amu
    • Abundance (\( a_3 \)): 3.1% = 0.031

    Contribution to average atomic mass: \[ m_3 \cdot a_3 = 29.974 \cdot 0.031 = 0.930 \]

Now, let's sum these contributions to find the average atomic mass of silicon:

\[ M = 25.758 + 1.360 + 0.930 = 28.048 , \text{amu} \]

Thus, the average atomic mass of silicon is approximately:

\[ \boxed{28.085 , \text{amu}} \]

(Note: The result may slightly vary based on rounding in intermediate steps.)