In a right triangle with side lengths of 3, 4, and 5 units, the angle θ (which is the smallest angle) corresponds to the two shorter sides: 3 (opposite side) and 4 (adjacent side). We can find sin θ as follows:
The sine of an angle is defined as the ratio of the length of the opposite side to the length of the hypotenuse. In this case, we want to find sin θ, where the opposite side is 3, and the hypotenuse is 5.
So, we calculate:
\[ \sin θ = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{3}{5} \]
Thus, sin θ equals \(\frac{3}{5}\). Therefore, the correct response is:
Start Fraction 3 over 5 End Fraction
1 answer