To solve the inequality \( x + \frac{1}{3} > 4 \), we first isolate \( x \):
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Subtract \( \frac{1}{3} \) from both sides: \[ x > 4 - \frac{1}{3} \]
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Convert 4 to a fraction: \[ 4 = \frac{12}{3} \]
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Now, perform the subtraction: \[ x > \frac{12}{3} - \frac{1}{3} = \frac{11}{3} \]
Next, convert \( \frac{11}{3} \) into a mixed number: \[ \frac{11}{3} = 3\frac{2}{3} \approx 3.67 \]
The solution to the inequality is \( x > \frac{11}{3} \) or \( x > 3.67 \).
On a number line, this would be indicated by an open circle at \( \frac{11}{3} \) (which is approximately \( 3.67 \), or \( 3\frac{2}{3} \)) and a line extending to the right towards positive infinity.
Based on this analysis, you should look for the graph that has:
- An open circle at \( \frac{11}{3} \) (or around 3.67).
- A line drawn to the right towards positive infinity.
If none of the responses directly mention \( \frac{11}{3} \), remember it is also equal to \( 3.67 \), so find the depiction closest to that value going towards positive infinity.