Question
Value of Cos 75 degree is
Answers
GPT-4o mini
The value of \( \cos 75^\circ \) can be calculated using the angle sum identity for cosine:
\[
\cos(75^\circ) = \cos(45^\circ + 30^\circ) = \cos(45^\circ) \cos(30^\circ) - \sin(45^\circ) \sin(30^\circ)
\]
Now, we know the values of the trigonometric functions at these angles:
- \( \cos(45^\circ) = \frac{\sqrt{2}}{2} \)
- \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \)
- \( \cos(30^\circ) = \frac{\sqrt{3}}{2} \)
- \( \sin(30^\circ) = \frac{1}{2} \)
Plugging these values into the identity:
\[
\cos(75^\circ) = \left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{3}}{2}\right) - \left(\frac{\sqrt{2}}{2}\right)\left(\frac{1}{2}\right)
\]
Calculating this gives:
\[
\cos(75^\circ) = \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4} = \frac{\sqrt{6} - \sqrt{2}}{4}
\]
So, the value of \( \cos 75^\circ \) is:
\[
\cos(75^\circ) = \frac{\sqrt{6} - \sqrt{2}}{4}
\]
\[
\cos(75^\circ) = \cos(45^\circ + 30^\circ) = \cos(45^\circ) \cos(30^\circ) - \sin(45^\circ) \sin(30^\circ)
\]
Now, we know the values of the trigonometric functions at these angles:
- \( \cos(45^\circ) = \frac{\sqrt{2}}{2} \)
- \( \sin(45^\circ) = \frac{\sqrt{2}}{2} \)
- \( \cos(30^\circ) = \frac{\sqrt{3}}{2} \)
- \( \sin(30^\circ) = \frac{1}{2} \)
Plugging these values into the identity:
\[
\cos(75^\circ) = \left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{3}}{2}\right) - \left(\frac{\sqrt{2}}{2}\right)\left(\frac{1}{2}\right)
\]
Calculating this gives:
\[
\cos(75^\circ) = \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4} = \frac{\sqrt{6} - \sqrt{2}}{4}
\]
So, the value of \( \cos 75^\circ \) is:
\[
\cos(75^\circ) = \frac{\sqrt{6} - \sqrt{2}}{4}
\]