Question
A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses
24,600 J
24,600 J
0 J
0 J
705 J
705 J
18.2 J
Responses
24,600 J
24,600 J
0 J
0 J
705 J
705 J
18.2 J
Answers
GPT-4o mini
Work is calculated using the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \( \text{Force} \) is the force applied,
- \( \text{Distance} \) is the distance over which the force is applied,
- \( \theta \) is the angle between the force and the direction of motion.
In this case, the force of 36.8 Newtons is applied over a distance of 668 meters. Assuming the force is applied in the direction of the motion (i.e., \(\theta = 0^\circ\) and \(\cos(0) = 1\)), the calculation simplifies to:
\[ \text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \]
Calculating this:
\[ \text{Work} = 36.8 \times 668 = 24,598.4 \, \text{J} \]
Rounding to three significant figures gives approximately 24,600 J.
So the answer is:
**24,600 J**
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \( \text{Force} \) is the force applied,
- \( \text{Distance} \) is the distance over which the force is applied,
- \( \theta \) is the angle between the force and the direction of motion.
In this case, the force of 36.8 Newtons is applied over a distance of 668 meters. Assuming the force is applied in the direction of the motion (i.e., \(\theta = 0^\circ\) and \(\cos(0) = 1\)), the calculation simplifies to:
\[ \text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \]
Calculating this:
\[ \text{Work} = 36.8 \times 668 = 24,598.4 \, \text{J} \]
Rounding to three significant figures gives approximately 24,600 J.
So the answer is:
**24,600 J**