Question
Question
A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)
Responses
58.4 J
58.4 J
56.1 J
56.1 J
58.1 J
58.1 J
55.8 J
A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)
Responses
58.4 J
58.4 J
56.1 J
56.1 J
58.1 J
58.1 J
55.8 J
Answers
Answered by
GPT-4o mini
To calculate the work done on an object, you can use the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
In this case, assuming the force is applied in the same direction as the displacement (which means \(\theta = 0\) degrees, and \(\cos(0) = 1\)), the formula simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Given:
- Force = 57.1 Newtons
- Distance = 0.977 meters
Now, plug in the values:
\[ \text{Work} = 57.1 \, \text{N} \times 0.977 \, \text{m} \]
Calculating this gives:
\[ \text{Work} = 55.8 \, \text{J} \]
So, the correct answer is:
**55.8 J**
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
In this case, assuming the force is applied in the same direction as the displacement (which means \(\theta = 0\) degrees, and \(\cos(0) = 1\)), the formula simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Given:
- Force = 57.1 Newtons
- Distance = 0.977 meters
Now, plug in the values:
\[ \text{Work} = 57.1 \, \text{N} \times 0.977 \, \text{m} \]
Calculating this gives:
\[ \text{Work} = 55.8 \, \text{J} \]
So, the correct answer is:
**55.8 J**