A bowling ball has a mass of 5 kg.

What happens to its momentum when its speed increases from 1 m/s to 2 m/s?

Responses

The initial momentum is ​5 kg⋅m/s​, and the final momentum is 10 kg⋅m/s.

The initial momentum is ​ 5 kilograms times meters per second ​ , and the final momentum is 10 kilograms times meters per second .

The initial momentum is ​5 kg⋅m/s​, and the final momentum is 7 kg⋅m/s.

The initial momentum is ​ 5 kilograms times meters per second ​ , and the final momentum is 7 kilograms times meters per second .

The initial momentum is ​5 kg⋅m/s​, and the final momentum is 20 kg⋅m/s.

The initial momentum is ​ 5 kilograms times meters per second ​ , and the final momentum is 20 kilograms times meters per second .

The initial momentum is ​5 kg⋅m/s​, and the final momentum is 3 kg⋅m/s.

1 answer

Momentum (p) is calculated using the formula:

\[ p = m \cdot v \]

where \( m \) is the mass and \( v \) is the velocity.

For the bowling ball with a mass of 5 kg:

  1. Initial momentum when the speed is 1 m/s: \[ p_{\text{initial}} = 5 \text{ kg} \times 1 \text{ m/s} = 5 \text{ kg⋅m/s} \]

  2. Final momentum when the speed is 2 m/s: \[ p_{\text{final}} = 5 \text{ kg} \times 2 \text{ m/s} = 10 \text{ kg⋅m/s} \]

Thus, the correct responses are:

  • The initial momentum is ​5 kg⋅m/s​, and the final momentum is 10 kg⋅m/s.
  • The initial momentum is ​ 5 kilograms times meters per second ​, and the final momentum is 10 kilograms times meters per second.