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A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s? Responses The ini...Question
A bowling ball has a mass of 5 kg.
What happens to its momentum when its speed increases from 1 m/s to 2 m/s?
Responses
The initial momentum is 5 kg⋅m/s, and the final momentum is 10 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 10 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 7 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 7 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 20 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 20 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 3 kg⋅m/s.
What happens to its momentum when its speed increases from 1 m/s to 2 m/s?
Responses
The initial momentum is 5 kg⋅m/s, and the final momentum is 10 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 10 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 7 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 7 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 20 kg⋅m/s.
The initial momentum is 5 kilograms times meters per second , and the final momentum is 20 kilograms times meters per second .
The initial momentum is 5 kg⋅m/s, and the final momentum is 3 kg⋅m/s.
Answers
GPT-4o mini
Momentum (p) is calculated using the formula:
\[ p = m \cdot v \]
where \( m \) is the mass and \( v \) is the velocity.
For the bowling ball with a mass of 5 kg:
1. **Initial momentum** when the speed is 1 m/s:
\[ p_{\text{initial}} = 5 \text{ kg} \times 1 \text{ m/s} = 5 \text{ kg⋅m/s} \]
2. **Final momentum** when the speed is 2 m/s:
\[ p_{\text{final}} = 5 \text{ kg} \times 2 \text{ m/s} = 10 \text{ kg⋅m/s} \]
Thus, the correct responses are:
- The initial momentum is 5 kg⋅m/s, and the final momentum is 10 kg⋅m/s.
- The initial momentum is 5 kilograms times meters per second , and the final momentum is 10 kilograms times meters per second.
\[ p = m \cdot v \]
where \( m \) is the mass and \( v \) is the velocity.
For the bowling ball with a mass of 5 kg:
1. **Initial momentum** when the speed is 1 m/s:
\[ p_{\text{initial}} = 5 \text{ kg} \times 1 \text{ m/s} = 5 \text{ kg⋅m/s} \]
2. **Final momentum** when the speed is 2 m/s:
\[ p_{\text{final}} = 5 \text{ kg} \times 2 \text{ m/s} = 10 \text{ kg⋅m/s} \]
Thus, the correct responses are:
- The initial momentum is 5 kg⋅m/s, and the final momentum is 10 kg⋅m/s.
- The initial momentum is 5 kilograms times meters per second , and the final momentum is 10 kilograms times meters per second.