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Question

Solve for x in the following equation: 272x−5+1=2
.(1 point)
Responses

0
0

8
8

16
16

11

1 answer

To solve the equation \( 272^{x-5} + 1 = 2 \), we can start by isolating the term with \( x \).

  1. Subtract 1 from both sides of the equation: \[ 272^{x-5} = 1 \]

  2. Recall that \( 272^0 = 1 \). This means we can set the exponent equal to 0: \[ x - 5 = 0 \]

  3. Solve for \( x \): \[ x = 5 \]

Since 5 is not one of the response options provided (0, 8, 16, 11), please check the original equation or the set of provided answers as there may be a mistake in interpreting the equation or the answer choices.