Question
How would an electron shell model of an oxygen atom (O) appear after the atom has formed chemical bonds?
It would have six electrons in the outermost shell.
It would have six electrons in the innermost shell.
It would have eight electrons in the outermost shell.
It would have eight electrons in the innermost shell.
It would have six electrons in the outermost shell.
It would have six electrons in the innermost shell.
It would have eight electrons in the outermost shell.
It would have eight electrons in the innermost shell.
Answers
GPT-4o mini
In the case of an oxygen atom, it has six electrons in its outermost shell (the second shell), which corresponds to its atomic number of 8 (2 in the innermost shell, and 6 in the outermost shell).
When oxygen forms chemical bonds, it typically does so by sharing electrons (as in covalent bonds), often with other atoms such as hydrogen. Through this process, it aims to achieve a stable electron configuration, which is typically one resembling that of the nearest noble gas (in this case, neon).
When oxygen forms bonds (for example, with two hydrogen atoms to create water, H₂O), the sharing of electrons effectively allows it to treat the electrons it is sharing as part of its own outer shell configuration. This can lead to oxygen having a total of eight electrons effectively participating in chemical bonding (two of its six and two shared from hydrogen).
So, after forming chemical bonds, in terms of the electron shell model, you would describe oxygen as having eight electrons in its outermost shell. However, it's important to note that the physical count of electrons has not changed; it's the effective electron configuration that appears to involve eight electrons.
Therefore, the correct answer would be:
**It would have eight electrons in the outermost shell.**
When oxygen forms chemical bonds, it typically does so by sharing electrons (as in covalent bonds), often with other atoms such as hydrogen. Through this process, it aims to achieve a stable electron configuration, which is typically one resembling that of the nearest noble gas (in this case, neon).
When oxygen forms bonds (for example, with two hydrogen atoms to create water, H₂O), the sharing of electrons effectively allows it to treat the electrons it is sharing as part of its own outer shell configuration. This can lead to oxygen having a total of eight electrons effectively participating in chemical bonding (two of its six and two shared from hydrogen).
So, after forming chemical bonds, in terms of the electron shell model, you would describe oxygen as having eight electrons in its outermost shell. However, it's important to note that the physical count of electrons has not changed; it's the effective electron configuration that appears to involve eight electrons.
Therefore, the correct answer would be:
**It would have eight electrons in the outermost shell.**