To solve the quadratic equation \(4x^2 + 2x = 10\), we first rearrange it to standard form:
\[ 4x^2 + 2x - 10 = 0 \]
Next, we can use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 4\), \(b = 2\), and \(c = -10\).
Calculating the discriminant:
\[ b^2 - 4ac = 2^2 - 4 \cdot 4 \cdot (-10) = 4 + 160 = 164 \]
Now substituting into the quadratic formula:
\[ x = \frac{-2 \pm \sqrt{164}}{2 \cdot 4} \]
Calculating \(\sqrt{164}\):
\[ \sqrt{164} \approx 12.81 \]
Now substituting back into the formula:
\[ x = \frac{-2 \pm 12.81}{8} \]
Calculating the two potential solutions:
- Using the plus sign:
\[ x = \frac{-2 + 12.81}{8} \approx \frac{10.81}{8} \approx 1.35 \]
- Using the minus sign:
\[ x = \frac{-2 - 12.81}{8} \approx \frac{-14.81}{8} \approx -1.85 \]
Rounding to the nearest hundredth, we get:
- The solutions are approximately \(x \approx 1.35\) and \(x \approx -1.85\).
From the provided responses, \(x = -1.85\) matches one of the solutions.
Thus, the correct answer is:
x = −1.85