Question
A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105 gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses
5.478×105lb.
5.478 times 10 superscript 5 baseline lb.
54.78×105lb.
54.78 times 10 superscript 5 baseline lb.
54.78×106 lb.
54.78 times 10 superscript 6 baseline lb.
5.478×106lb.
Responses
5.478×105lb.
5.478 times 10 superscript 5 baseline lb.
54.78×105lb.
54.78 times 10 superscript 5 baseline lb.
54.78×106 lb.
54.78 times 10 superscript 6 baseline lb.
5.478×106lb.
Answers
GPT-4o mini
To find the weight of the water in an Olympic-sized swimming pool, we can multiply the volume of the pool by the weight of one gallon of water.
1. **Weight of water in one gallon**: 8.3 lb
2. **Volume of an Olympic-sized swimming pool**: \(6.6 \times 10^5\) gallons
Now, we calculate the total weight:
\[
\text{Total weight} = \text{Volume} \times \text{Weight per gallon}
\]
\[
\text{Total weight} = (6.6 \times 10^5 \text{ gallons}) \times (8.3 \text{ lb/gallon})
\]
\[
\text{Total weight} = 54.78 \times 10^5 \text{ lb}
\]
Now we need to convert this to proper scientific notation:
\[
54.78 \times 10^5 \text{ lb} = 5.478 \times 10^{6} \text{ lb}
\]
Thus, the approximate weight of the water in an Olympic-sized swimming pool is:
\[
\boxed{5.478 \times 10^6 \text{ lb}}
\]
1. **Weight of water in one gallon**: 8.3 lb
2. **Volume of an Olympic-sized swimming pool**: \(6.6 \times 10^5\) gallons
Now, we calculate the total weight:
\[
\text{Total weight} = \text{Volume} \times \text{Weight per gallon}
\]
\[
\text{Total weight} = (6.6 \times 10^5 \text{ gallons}) \times (8.3 \text{ lb/gallon})
\]
\[
\text{Total weight} = 54.78 \times 10^5 \text{ lb}
\]
Now we need to convert this to proper scientific notation:
\[
54.78 \times 10^5 \text{ lb} = 5.478 \times 10^{6} \text{ lb}
\]
Thus, the approximate weight of the water in an Olympic-sized swimming pool is:
\[
\boxed{5.478 \times 10^6 \text{ lb}}
\]