In the given chemical equation:
\[ \text{Pb(NO}_3\text{)}_2 + 2\text{NaCl} \rightarrow 2\text{NaNO}_3 + \text{PbCl}_2 \]
The compound PbCl₂ (lead(II) chloride) is the precipitate.
In this reaction, lead(II) chloride is formed when lead(II) nitrate reacts with sodium chloride. PbCl₂ is sparingly soluble in water and will precipitate out of the solution, while sodium nitrate (NaNO₃) remains dissolved in the aqueous solution. Thus, PbCl₂ is the solid precipitate formed in this reaction.