Question
The Punnett square below shows the results of a genetic cross. The mother is heterozygous for the trait shown. The father is homozygous recessive for the trait.
Image
What can one predict from the results of the Punnett square?
A.
All the offspring will have the same genotype as the mother.
B.
All the offspring will have the same phenotype as the father.
C.
There is a 50% chance that the offspring will have the same phenotype and genotype as the father.
D.
There is a 25% chance that the offspring will have the same phenotype and genotype as the mother.
Image
What can one predict from the results of the Punnett square?
A.
All the offspring will have the same genotype as the mother.
B.
All the offspring will have the same phenotype as the father.
C.
There is a 50% chance that the offspring will have the same phenotype and genotype as the father.
D.
There is a 25% chance that the offspring will have the same phenotype and genotype as the mother.
Answers
GPT-4o mini
To analyze the question, we need to understand the genotypes of the parents and what the Punnett square results would indicate.
1. The mother is heterozygous, which means her genotype is typically represented as "Aa" (where "A" is the dominant allele and "a" is the recessive allele).
2. The father is homozygous recessive, represented as "aa."
When we set up a Punnett square for the cross between these two parents (Aa x aa), the resulting genotypes of the offspring would be as follows:
- The potential offspring genotypes are:
- A from the mother and a from the father → Aa (heterozygous, displays the dominant phenotype)
- a from the mother and a from the father → aa (homozygous recessive, displays the recessive phenotype)
Based on this cross, the possible combinations (results from the Punnett square) would be:
- 50% Aa (dominant phenotype)
- 50% aa (recessive phenotype)
Now, let's evaluate the multiple-choice options:
A. All the offspring will have the same genotype as the mother.
**False.** Only half will have the mother's genotype (Aa).
B. All the offspring will have the same phenotype as the father.
**False.** Only half will have the same phenotype as the father (aa), the other half (Aa) will display a different (dominant) phenotype.
C. There is a 50% chance that the offspring will have the same phenotype and genotype as the father.
**False.** While it is true that there is a 50% chance they will have the same phenotype as the father, the offspring cannot have the same genotype (aa) as the father since the mother is heterozygous.
D. There is a 25% chance that the offspring will have the same phenotype and genotype as the mother.
**False.** There is a 50% chance (not 25%) that the offspring will have the same genotype as the mother (Aa) and therefore the same phenotype.
After evaluating all choices it appears I made an error in my original conclusion. I will review the options based on the above cross results, we can see that:
- The offspring would show a 50% chance of having the dominant phenotype and genotype of the mother (Aa) and a 50% chance of having the recessive phenotype and genotype of the father (aa).
Based on that, we cannot choose any of the options provided as they're all inaccurate. The correct understanding would be:
- 50% Aa (dominant phenotype)
- 50% aa (recessive phenotype)
None of the provided options correctly reflect this understanding.
1. The mother is heterozygous, which means her genotype is typically represented as "Aa" (where "A" is the dominant allele and "a" is the recessive allele).
2. The father is homozygous recessive, represented as "aa."
When we set up a Punnett square for the cross between these two parents (Aa x aa), the resulting genotypes of the offspring would be as follows:
- The potential offspring genotypes are:
- A from the mother and a from the father → Aa (heterozygous, displays the dominant phenotype)
- a from the mother and a from the father → aa (homozygous recessive, displays the recessive phenotype)
Based on this cross, the possible combinations (results from the Punnett square) would be:
- 50% Aa (dominant phenotype)
- 50% aa (recessive phenotype)
Now, let's evaluate the multiple-choice options:
A. All the offspring will have the same genotype as the mother.
**False.** Only half will have the mother's genotype (Aa).
B. All the offspring will have the same phenotype as the father.
**False.** Only half will have the same phenotype as the father (aa), the other half (Aa) will display a different (dominant) phenotype.
C. There is a 50% chance that the offspring will have the same phenotype and genotype as the father.
**False.** While it is true that there is a 50% chance they will have the same phenotype as the father, the offspring cannot have the same genotype (aa) as the father since the mother is heterozygous.
D. There is a 25% chance that the offspring will have the same phenotype and genotype as the mother.
**False.** There is a 50% chance (not 25%) that the offspring will have the same genotype as the mother (Aa) and therefore the same phenotype.
After evaluating all choices it appears I made an error in my original conclusion. I will review the options based on the above cross results, we can see that:
- The offspring would show a 50% chance of having the dominant phenotype and genotype of the mother (Aa) and a 50% chance of having the recessive phenotype and genotype of the father (aa).
Based on that, we cannot choose any of the options provided as they're all inaccurate. The correct understanding would be:
- 50% Aa (dominant phenotype)
- 50% aa (recessive phenotype)
None of the provided options correctly reflect this understanding.