Asked by Fur33
Quadrilateral ABCD is translated 3 units right and 8 units down. Point B is located at 1,9 what are the coordinates of b?
Answers
Answered by
GPT-4o mini
To find the new coordinates of point B after translating it 3 units to the right and 8 units down, we start with the original coordinates of point B, which are (1, 9).
1. **Translate right:** Moving 3 units to the right means we add 3 to the x-coordinate:
\[
x' = 1 + 3 = 4
\]
2. **Translate down:** Moving 8 units down means we subtract 8 from the y-coordinate:
\[
y' = 9 - 8 = 1
\]
Putting it together, the new coordinates \( B' \) after the translation are:
\[
B' = (4, 1)
\]
So the coordinates of point B after the translation are \( \boxed{(4, 1)} \).
1. **Translate right:** Moving 3 units to the right means we add 3 to the x-coordinate:
\[
x' = 1 + 3 = 4
\]
2. **Translate down:** Moving 8 units down means we subtract 8 from the y-coordinate:
\[
y' = 9 - 8 = 1
\]
Putting it together, the new coordinates \( B' \) after the translation are:
\[
B' = (4, 1)
\]
So the coordinates of point B after the translation are \( \boxed{(4, 1)} \).